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  4. A container of volume V, contains 0.28 g of N2 gas. If same volume of an unknown gas under similar conditions of temperature and pressure weighs 0.44g, the molecular mass of the gas is

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Q. A container of volume V, contains 0.28 g of $N_2$ gas. If same volume of an unknown gas under similar conditions of temperature and pressure weighs 0.44g, the molecular mass of the gas is

Some Basic Concepts of Chemistry

Solution:

Ratio of the masses of equal volumes of two gases under similar conditions is the same as the ratio of their molecular masses
Thus, $\frac{M_{\left(G\right)}}{M_{\left(N_2\right)}}=\frac{0.44}{0.28}$
$\therefore M_{\left(G\right)}=\frac{0.44}{0.28}\times28$
$=44$