A constant torque of 2000 N - m, turns a wheel of moment of inertia 300 kg - m 2 about an axis through the centre. Angular velocity of the wheel after 5 s will be

Question

A constant torque of 2000 N - m, turns a wheel of moment of inertia 300 kg - m 2 about an axis through the centre. Angular velocity of the wheel after 5 s will be (A) 33.3 rad / s 2 (B) 4.44 rad / s 2 (C) 50 rad / s 2 (D) None

Tardigrade Admin · Accepted Answer

τ=I α ⇒ α=(τ/I) =(2000/300) =(20/3) rad / s 2 ω=ω0+α t=0+(20/3) × 5=(100/3) =33.3 rad / s 2

Q. A constant torque of $2000 N - m$ , turns a wheel of moment of inertia $300 k g - m^{2}$ about an axis through the centre. Angular velocity of the wheel after $5 s$ will be

$33.3 r a d / s^{2}$

$4.44 r a d / s^{2}$

$50 r a d / s^{2}$

None

$τ = I α \Rightarrow$
$α = \frac{τ}{I}$
$= \frac{2000}{300}$
$= \frac{20}{3} r a d / s^{2}$
$ω = ω_{0} + α t = 0 + \frac{20}{3} \times 5 = \frac{100}{3}$
$= 33.3 r a d / s^{2}$

Q. A constant torque of 2000N−m, turns a wheel of moment of inertia 300kg−m2 about an axis through the centre. Angular velocity of the wheel after 5s will be

33.3rad/s2

4.44rad/s2

50rad/s2