A constant torque of 1000 N-m turns a wheel of moment of inertia 200 text kg-m2 about an axis through its centre. Its angular velocity after 3 second is, in rad/s:

Question

A constant torque of 1000 N-m turns a wheel of moment of inertia 200 text kg-m2 about an axis through its centre. Its angular velocity after 3 second is, in rad/s: (A) 1 (B) 5 (C) 15 (D) 10

Tardigrade Admin · Accepted Answer

The formula for torque is as τ =Iα where I is moment of inertia and α is the angular acceleration α =(τ /I)=(1000/200)=5 rad/s2 ( beginalign textGiven: τ =1000N I text = text 2000 kg-m2 textt = 3s endalign ) Now, angular velocity ω =α t=5× 3 =15 rad/s

Q. A constant torque of 1000 N-m turns a wheel of moment of inertia $200 k g - m^{2}$ about an axis through its centre. Its angular velocity after 3 second is, in rad/s:

1

5

15

10

The formula for torque is as $τ = I α$ where $I$ is moment of inertia and $α$ is the angular acceleration $α = \frac{τ}{I} = \frac{1000}{200} = 5 r a d / s^{2}$ $⎝ ⎛ Given: τ = 1000 N I = 2000 k g - m^{2} t = 3s ⎠ ⎞$ Now, angular velocity $ω = α t = 5 \times 3$ $= 15 r a d / s$

Q. A constant torque of 1000 N-m turns a wheel of moment of inertia 200kg−m2 about an axis through its centre. Its angular velocity after 3 second is, in rad/s:

1

5

15

10

The formula for torque is as τ=Iα where I is moment of inertia and α is the angular acceleration α=Iτ​=2001000​=5rad/s2 ⎝⎛​​Given:τ=1000NI=2000kg−m2t = 3s ​⎠⎞​ Now, angular velocity ω=αt=5×3 =15rad/s

Q. A constant torque of 1000 N-m turns a wheel of moment of inertia $200 k g - m^{2}$ about an axis through its centre. Its angular velocity after 3 second is, in rad/s:

The formula for torque is as $τ = I α$ where $I$ is moment of inertia and $α$ is the angular acceleration $α = \frac{τ}{I} = \frac{1000}{200} = 5 r a d / s^{2}$ $⎝ ⎛ Given: τ = 1000 N I = 2000 k g - m^{2} t = 3s ⎠ ⎞$ Now, angular velocity $ω = α t = 5 \times 3$ $= 15 r a d / s$