A constant current was passed through a solution of AuCl 4 ominus ion between gold electrodes. After a period of 10.0 min, the increase in the weight of cathode was 1.314 g. The total charge passed through solution is (atomic weight of AuCl 4 ominus=339 )

Question

A constant current was passed through a solution of AuCl 4 ominus ion between gold electrodes. After a period of 10.0 min, the increase in the weight of cathode was 1.314 g. The total charge passed through solution is (atomic weight of AuCl 4 ominus=339 ) (A) 1.16 × 10-2 F (B) 3.5 × 10-2 F (C) 2 × 10-2 F (D) 4 × 10-3 F

Tardigrade Admin · Accepted Answer

Au 3++3 e- arrow Au (W/197 / 3)=( text Charge /96500) ∴ Charge =(1.314 × 3 × F/197)=0.02 F

Q. A constant current was passed through a solution of $A u C l_{4}^{⊖}$ ion between gold electrodes. After a period of $10.0 min$ , the increase in the weight of cathode was $1.314 g$ . The total charge passed through solution is (atomic weight of $A u C l_{4}^{⊖} = 339$ )

$1.16 \times 1 0^{- 2} F$

$3.5 \times 1 0^{- 2} F$

$2 \times 1 0^{- 2} F$

$4 \times 1 0^{- 3} F$

$A u^{3 +} + 3 e^{-} \to A u$
$\frac{W}{197/3} = \frac{Charge}{96500}$
$∴$ Charge $= \frac{1.314 \times 3 \times F}{197} = 0.02 F$

Q. A constant current was passed through a solution of AuCl4⊖​ ion between gold electrodes. After a period of 10.0min, the increase in the weight of cathode was 1.314g. The total charge passed through solution is (atomic weight of AuCl4⊖​=339 )

1.16×10−2F

3.5×10−2F

2×10−2F

4×10−3F