A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is

Question

A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is (A) E π R2 (B) E R h (C) (E h R/2) (D) E h2

Tardigrade Admin · Accepted Answer

Plane normal to electric field is a triangle with base length 2 R and height h. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5ac703913ec440e9733d8737ee444a0f-.png" /> Area of triangle A=(1/2) × 2 R h=R h Electric flux entering the cone =E A=E R h

Q. A cone lies in a uniform electric field $E$ as shown in figure. The electric flux entering the cone is

$E π R^{2}$

$ER h$

$\frac{E h R}{2}$

$E h^{2}$

Plane normal to electric field is a triangle with base length $2 R$ and height $h$ .

Area of triangle $A = \frac{1}{2} \times 2 R h = R h$
Electric flux entering the cone $= E A = ER h$

Q. A cone lies in a uniform electric field E as shown in figure. The electric flux entering the cone is

EπR2

ERh

2EhR​

Eh2