A conducting wire of cross-sectional area 1 cm2 has 3× 1023 charge carriers per metre3 . If wire carries a current 24 mA, then rift velocity of carriers is

Question

A conducting wire of cross-sectional area 1 cm2 has 3× 1023 charge carriers per metre3 . If wire carries a current 24 mA, then rift velocity of carriers is (A)  5× 10-2m/s  (B)  0.5 text m/s  (C)  5× 10-3 text m/s  (D)  5× 10-6 text m/s

Tardigrade Admin · Accepted Answer

The current i crossing area of cross-section A can be expressed in terms of drift velocity vd and the moving charges as i=n e vd A where, n is number of charge carriers per unit volume and e the charge on the carrier. ∴ vd =(i/n e A)=(24 × 10-3/(3 × 1023)(1.6 × 10-19)(10-4)) =5 × 10-3 m / s

Q. A conducting wire of cross-sectional area 1 $c m^{2}$ has $3 \times 10^{23}$ charge carriers per $m e t r e^{3}$ . If wire carries a current $24 m A$ , then rift velocity of carriers is

$5 \times 10^{- 2} m / s$

$0.5 m / s$

$5 \times 10^{- 3} m / s$

$5 \times 10^{- 6} m / s$

Q. A conducting wire of cross-sectional area 1 cm2 has 3×1023 charge carriers per metre3 . If wire carries a current 24mA, then rift velocity of carriers is

5×10−2m/s

0.5m/s

5×10−3m/s

5×10−6m/s

The current i crossing area of cross-section A can be expressed in terms of drift velocity vd​ and the moving charges as i=nevd​A where, n is number of charge carriers per unit volume and e the charge on the carrier. ∴vd​=neAi​=(3×1023)(1.6×10−19)(10−4)24×10−3​ =5×10−3m/s

Q. A conducting wire of cross-sectional area 1 $c m^{2}$ has $3 \times 10^{23}$ charge carriers per $m e t r e^{3}$ . If wire carries a current $24 m A$ , then rift velocity of carriers is

$5 \times 10^{- 2} m / s$

$0.5 m / s$

$5 \times 10^{- 3} m / s$

$5 \times 10^{- 6} m / s$