Question

A conducting sphere of radius 30 cm is given a charge of $1.2\times {10}^{-8}C$ . What will be its potential?

• A. 0.03kV
• B. 0.9kV
• C. 1.8kV
• D. 3.6kV

Answer 1

Answer: (C)

Here, $C=4\pi {\epsilon }_{0}R$ $V=\frac{q}{C}=\frac{2\times {10}^{-8}}{4\pi {\epsilon }_{0}R}$ $=\frac{9\times {10}^9\times 2\times {10}^{-3}}{10\times {10}^{-2}}$ $=1.8\times {10}^{3}V=1.8kV$