A conducting rod AC of length 4 l is rotated about a point O in a uniform magnetic field B directed into the paper AO=l and OC=3 l, then

Question

A conducting rod AC of length 4 l is rotated about a point O in a uniform magnetic field B directed into the paper AO=l and OC=3 l, then (A)  VA-VO=(Bω l2/2)  (B)  VO-VC=(9/2)Bω l2  (C)  VA-VC=4Bω l2  (D)  VC-VO=(9/2)Bω l2

Tardigrade Admin · Accepted Answer

V0-VA=(B ω I/2)× I =(B ω I2/2) V0-VA=(B ω 3I/2)× 3I =(9B ω I2/2) VA-Vc=4Bω I2

Q. A conducting rod AC of length $4 l$ is rotated about a point O in a uniform magnetic field B directed into the paper $A O = l$ and $OC = 3 l,$ then

$V_{A} - V_{O} = \frac{B ω l ^{2}}{2}$

$V_{O} - V_{C} = \frac{9}{2} B ω l^{2}$

$V_{A} - V_{C} = 4 B ω l^{2}$

$V_{C} - V_{O} = \frac{9}{2} B ω l^{2}$

$V_{0} - V_{A} = \frac{B ω I}{2} \times I$ $= \frac{B ω I ^{2}}{2}$ $V_{0} - V_{A} = \frac{B ω 3 I}{2} \times 3 I$ $= \frac{9 B ω I ^{2}}{2}$ $V_{A} - V_{c} = 4 B ω I^{2}$

Q. A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field B directed into the paper AO=l and OC=3l, then

VA​−VO​=2Bωl2​

VO​−VC​=29​Bωl2

VA​−VC​=4Bωl2

VC​−VO​=29​Bωl2