A condenser of 2 μ F capacitance is charged steadily from 0 to 5 C. Which of the following graph represents correctly the variation of potential difference (V) across it's plates with respect to the charge ( Q ) on the condenser?

Question

A condenser of 2 μ F capacitance is charged steadily from 0 to 5 C. Which of the following graph represents correctly the variation of potential difference (V) across it's plates with respect to the charge ( Q ) on the condenser? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Q = CV V =(1/ C ) Q Straight line with slope =(1/ C ) Slope =(1/C)=(1/2 × 10-6)=5 × 105

Q. A condenser of $2 μ F$ capacitance is charged steadily from $0$ to $5 C$ . Which of the following graph represents correctly the variation of potential difference $(V)$ across it's plates with respect to the charge $(Q)$ on the condenser?

$Q = C V$
$V = \frac{1}{C} Q$
Straight line with slope $= \frac{1}{C}$
Slope $= \frac{1}{C} = \frac{1}{2 \times 1 0 ^{- 6}} = 5 \times 1 0^{5}$

Q. A condenser of 2μF capacitance is charged steadily from 0 to 5C. Which of the following graph represents correctly the variation of potential difference (V) across it's plates with respect to the charge (Q) on the condenser?

Q=CV V=C1​Q Straight line with slope =C1​ Slope =C1​=2×10−61​=5×105

Q. A condenser of $2 μ F$ capacitance is charged steadily from $0$ to $5 C$ . Which of the following graph represents correctly the variation of potential difference $(V)$ across it's plates with respect to the charge $(Q)$ on the condenser?

$Q = C V$
$V = \frac{1}{C} Q$
Straight line with slope $= \frac{1}{C}$
Slope $= \frac{1}{C} = \frac{1}{2 \times 1 0 ^{- 6}} = 5 \times 1 0^{5}$