A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

Question

A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is (A) 2 (B) 5 (C) 4 (D) 6

Tardigrade Admin · Accepted Answer

Since each - COCH3 group displace one H atom in the reaction molecular mass increases with 42 unit. Since the mass increases by (390 - 180) = 210, hence the number of - NH2 group is =(210/42)=5.

Q. A compound with molecular mass $180$ is acylated with $C H_{3} COCl$ to get a compound with molecular mass $390$ . The number of amino groups present per molecule of the former compound is

2

5

4

6

Since each - $COC H_{3}$ group displace one H atom in the reaction molecular mass increases with 42 unit.
Since the mass increases by (390 - 180) = 210, hence the number of - $N H_{2}$ group is $= \frac{210}{42} = 5$ .

Q. A compound with molecular mass 180 is acylated with CH3​COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

2

5

4

6

Since each - COCH3​ group displace one H atom in the reaction molecular mass increases with 42 unit. Since the mass increases by (390 - 180) = 210, hence the number of - NH2​ group is =42210​=5.

Q. A compound with molecular mass $180$ is acylated with $C H_{3} COCl$ to get a compound with molecular mass $390$ . The number of amino groups present per molecule of the former compound is

Since each - $COC H_{3}$ group displace one H atom in the reaction molecular mass increases with 42 unit.
Since the mass increases by (390 - 180) = 210, hence the number of - $N H_{2}$ group is $= \frac{210}{42} = 5$ .