A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

Question

A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is (A) 1 (B) 3 (C) 5 (D) 4

Tardigrade Admin · Accepted Answer

R- undersetMN H2+CH3COCl arrow undersetM + 42R N H C O C H3+HCl If the increase in molecular mass is 42, the reactant has one NH2 group. Actual increase in molecular mass =390-180=210 Number of NH2 groups =(210/42)=5

Q. A compound with molecular mass 180 is acylated with $C H_{3} COCl$ to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

1

3

5

4

$R - M N H_{2} + C H_{3} COCl \to M + 42 RN H COC H_{3} + H Cl$

If the increase in molecular mass is 42, the reactant has one $N H_{2}$ group.

Actual increase in molecular mass $= 390 - 180 = 210$

Number of $N H_{2}$ groups $= \frac{210}{42} = 5$

Q. A compound with molecular mass 180 is acylated with CH3​COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

1

3

5

4

R−MNH2​​+CH3​COCl→M+42RNHCOCH3​​+HCl If the increase in molecular mass is 42, the reactant has one NH2​ group. Actual increase in molecular mass =390−180=210 Number of NH2​ groups =42210​=5

Q. A compound with molecular mass 180 is acylated with $C H_{3} COCl$ to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

$R - M N H_{2} + C H_{3} COCl \to M + 42 RN H COC H_{3} + H Cl$

If the increase in molecular mass is 42, the reactant has one $N H_{2}$ group.

Actual increase in molecular mass $= 390 - 180 = 210$

Number of $N H_{2}$ groups $= \frac{210}{42} = 5$