A compound (molar mass =120g ) contains 40 % carbon by mass. If the ratio of number of H and O atoms in the compound is 2:1 , then number of H -atoms in one molecule of the compound is :-

Question

A compound (molar mass =120g ) contains 40 % carbon by mass. If the ratio of number of H and O atoms in the compound is 2:1 , then number of H -atoms in one molecule of the compound is :- (A) 2 (B) 6 (C) 8 (D) 10

Tardigrade Admin · Accepted Answer

Mass of C=120× (40/100)=48g Suppose number of H and O atoms are 2x and x, then, 48+2x× 1+x× 16=120 18x=72 x=4

Q. A compound (molar mass $= 120 g$ ) contains $40%$ carbon by mass. If the ratio of number of $H$ and $O$ atoms in the compound is $2 : 1$ , then number of $H$ -atoms in one molecule of the compound is :-

$2$

$6$

$8$

$10$

Mass of $C = 120 \times \frac{40}{100} = 48 g$
Suppose number of $H$ and $O$ atoms are $2 x$ and
$x,$ then,
$48 + 2 x \times 1 + x \times 16 = 120$
$18 x = 72$
$x = 4$

Q. A compound (molar mass =120g ) contains 40% carbon by mass. If the ratio of number of H and O atoms in the compound is 2:1 , then number of H -atoms in one molecule of the compound is :-

2

6

8

10

Mass of C=120×10040​=48g Suppose number of H and O atoms are 2x and x, then, 48+2x×1+x×16=120 18x=72 x=4

Q. A compound (molar mass $= 120 g$ ) contains $40%$ carbon by mass. If the ratio of number of $H$ and $O$ atoms in the compound is $2 : 1$ , then number of $H$ -atoms in one molecule of the compound is :-

$2$

$6$

$8$

$10$

Mass of $C = 120 \times \frac{40}{100} = 48 g$
Suppose number of $H$ and $O$ atoms are $2 x$ and
$x,$ then,
$48 + 2 x \times 1 + x \times 16 = 120$
$18 x = 72$
$x = 4$