A compound microscope has magnifying power as 32 and magnifying power of eye-piece is 4, then the magnifying power of objective is -

Question

A compound microscope has magnifying power as 32 and magnifying power of eye-piece is 4, then the magnifying power of objective is - (A) 8 (B) 10 (C) 6 (D) 12

Tardigrade Admin · Accepted Answer

M.P. =m0 × me 32 =m0 × 4 ∴ m0 =8

Q. A compound microscope has magnifying power as 32 and magnifying power of eye-piece is $4,$ then the magnifying power of objective is -

8

10

6

12

$M . P . = m_{0} \times m_{e}$
$32 = m_{0} \times 4$
$∴ m_{0} = 8$

Q. A compound microscope has magnifying power as 32 and magnifying power of eye-piece is 4, then the magnifying power of objective is -

8

10

6

12

M.P.=m0​×me​ 32=m0​×4 ∴m0​=8

Q. A compound microscope has magnifying power as 32 and magnifying power of eye-piece is $4,$ then the magnifying power of objective is -

$M . P . = m_{0} \times m_{e}$
$32 = m_{0} \times 4$
$∴ m_{0} = 8$