A compound microscope consists of an objective lens with focal length 1.0 cm and eye piece of focal length 2.0 cm and a tube length 20 cm the magnification will be

Question

A compound microscope consists of an objective lens with focal length 1.0 cm and eye piece of focal length 2.0 cm and a tube length 20 cm the magnification will be (A) 100 (B) 200 (C) 250 (D) 300

Tardigrade Admin · Accepted Answer

Magnification, of compound microscope m = m0 × me = ((L/f0))×((D/fe)) Here, L = 20 cm, D = 25 cm (near point), f0 = 1 cm and fe = 2 cm ∴ m = (20/1)× (25/2) = 250

Q. A compound microscope consists of an objective lens with focal length $1.0 c m$ and eye piece of focal length $2.0 c m$ and a tube length $20 c m$ the magnification will be

$100$

$200$

$250$

$300$

Magnification, of compound microscope
$m = m_{0} \times m_{e} = (\frac{L}{f _{0}}) \times (\frac{D}{f _{e}})$
Here, $L = 20 c m, D = 25 c m$ (near point),
$f_{0} = 1 c m$ and $f_{e} = 2 c m$
$∴ m = \frac{20}{1} \times \frac{25}{2} = 250$

Q. A compound microscope consists of an objective lens with focal length 1.0cm and eye piece of focal length 2.0cm and a tube length 20cm the magnification will be

100

200

250

300