A compound has a haemoglobin-like structure. It has one Fe. It contains 4.6 % of Fe. The approximate molecular mass is

Question

A compound has a haemoglobin-like structure. It has one Fe. It contains 4.6 % of Fe. The approximate molecular mass is (A) 100 g mol -1 (B) 1200 g mol -1 (C) 1400 g mol -1 (D) 1600 g mol -1

Tardigrade Admin · Accepted Answer

1 g -atom of Fe (56 g Fe ) is present in I mole of the compound. As 4.6 g of Fe is present in 100 g of the compound. ∴ 56 g of Fe will be present in (100/4.6) × 56 g =1217 g of the compound Hence, approximate molecular mass =1200 g mol -1

Q. A compound has a haemoglobin-like structure. It has one $F e$ . It contains $4.6%$ of $F e$ . The approximate molecular mass is

$100 g m o l^{- 1}$

$1200 g m o l^{- 1}$

$1400 g m o l^{- 1}$

$1600 g m o l^{- 1}$

$1 g$ -atom of Fe $(56 g F e)$ is present in $I$ mole of the compound.

As $4.6 g$ of $F e$ is present in $100 g$ of the compound.

$∴ 56 g$ of $F e$ will be present in $\frac{100}{4.6} \times 56 g$

$= 1217 g$ of the compound

Hence, approximate molecular mass $= 1200 g m o l^{- 1}$

Q. A compound has a haemoglobin-like structure. It has one Fe. It contains 4.6% of Fe. The approximate molecular mass is

100gmol−1

1200gmol−1

1400gmol−1

1600gmol−1