A compound contains 28% N2 and 72% of a metal by weight. 3 atoms of the metal combines with 2 atoms of N. The atomic weight of metal is

Question

A compound contains 28% N2 and 72% of a metal by weight. 3 atoms of the metal combines with 2 atoms of N. The atomic weight of metal is (A) 12 (B) 32 (C) 24 (D) 16

Tardigrade Admin · Accepted Answer

Here 3 atoms of the metal combines with 2 atoms of N
Hence, the formula of the compound

= M_{3} N_{2}

Suppose the atomic weight of metal = X
28 g of nitrogen combines

= 3 X g

metal
From question, 28 g nitrogen combines = 72 g metal

3 X = 72

So

X = 24

Atomic weight of metal = 24.

Q. A compound contains 28% N2​ and 72% of a metal by weight. 3 atoms of the metal combines with 2 atoms of N. The atomic weight of metal is

12

32

24

16

Here 3 atoms of the metal combines with 2 atoms of N Hence, the formula of the compound =M3​N2​ Suppose the atomic weight of metal = X 28 g of nitrogen combines =3Xg metal From question, 28 g nitrogen combines = 72 g metal 3X=72 So X=24 Atomic weight of metal = 24.

Q. A compound contains 28% $N_{2}$ and 72% of a metal by weight. 3 atoms of the metal combines with 2 atoms of N. The atomic weight of metal is

Here 3 atoms of the metal combines with 2 atoms of N
Hence, the formula of the compound $= M_{3} N_{2}$
Suppose the atomic weight of metal = X
28 g of nitrogen combines $= 3 X g$ metal
From question, 28 g nitrogen combines = 72 g metal
$3 X = 72$
So $X = 24$
Atomic weight of metal = 24.