A compound (C5H8) reacts with ammoniacal AgNO3 to give a white precipitate and reacts with excess of KMnO4 solution to give (CH3)2CH - COOH. The compound is

Question

A compound (C5H8) reacts with ammoniacal AgNO3 to give a white precipitate and reacts with excess of KMnO4 solution to give (CH3)2CH - COOH. The compound is (A) CH2 = CH - CH = CH - CH3 (B) (CH3)2C H -C = CH (C) CH3(CH2)2C = CH (D) (CH3)2C = C = CH2

Tardigrade Admin · Accepted Answer

Correct answer is (b) (CH3)2C H -C = CH

Q. A compound $(C_{5} H_{8})$ reacts with ammoniacal $A g N O_{3}$ to give a white precipitate and reacts with excess of $K M n O_{4}$ solution to give $(C H_{3})_{2} C H - COO H$ . The compound is

$C H_{2} = C H - C H = C H - C H_{3}$

$(C H_{3})_{2} C H - C = C H$

$C H_{3} (C H_{2})_{2} C = C H$

$(C H_{3})_{2} C = C = C H_{2}$

Correct answer is (b) $(C H_{3})_{2} C H - C = C H$

Q. A compound (C5​H8​) reacts with ammoniacal AgNO3​ to give a white precipitate and reacts with excess of KMnO4​ solution to give (CH3​)2​CH−COOH. The compound is

CH2​=CH−CH=CH−CH3​

(CH3​)2​CH−C=CH

CH3​(CH2​)2​C=CH

(CH3​)2​C=C=CH2​