A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC = 1 k Ω and VCC = 10V. What is the minimum base current (in μ A) for VCE to reach saturation ?

Question

A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC = 1 k Ω and VCC = 10V. What is the minimum base current (in μ A) for VCE to reach saturation ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Given, b = 250 Voltage gain, (VCC/VB) = β (RC/RB) (10/VB) = (1/25 × 103) = 40 μ A

Q. A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is $250, R_{C} = 1 k Ω$ and $V_{CC} = 10 V$ . What is the minimum base current (in $μ A)$ for $V_{CE}$ to reach saturation ?

Given, $b = 250$
Voltage gain, $\frac{V _{CC}}{V _{B}} = β \frac{R _{C}}{R _{B}}$
$\frac{10}{V _{B}} = \frac{1}{25 \times 1 0 ^{3}} = 40 μ A$

Q. A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250,RC​=1kΩ and VCC​=10V. What is the minimum base current (in μA) for VCE​ to reach saturation ?

Given, b=250 Voltage gain, VB​VCC​​=βRB​RC​​ VB​10​=25×1031​=40μA

Q. A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is $250, R_{C} = 1 k Ω$ and $V_{CC} = 10 V$ . What is the minimum base current (in $μ A)$ for $V_{CE}$ to reach saturation ?

Given, $b = 250$
Voltage gain, $\frac{V _{CC}}{V _{B}} = β \frac{R _{C}}{R _{B}}$
$\frac{10}{V _{B}} = \frac{1}{25 \times 1 0 ^{3}} = 40 μ A$