A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2 V. The current reaches half of its steady state value in

Question

A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2 V. The current reaches half of its steady state value in (A) 0.15 s (B) 0.3 s (C) 0.05 s (D) 0.1 s

Tardigrade Admin · Accepted Answer

The charging of inductance is given by I = I0 [1 - e-Rt/L ] ∴ : (I0/2) = I0 [ 1 - e-RT/L ] or e-Rt/L = (1/2) or (Rt/L) = 1n 2 or t = (0.693 × 300 × 10-3/2) = 0.1 s

Q. A coil of inductance 300 mH and resistance 2 $Ω$ is connected to a source of voltage 2 V. The current reaches half of its steady state value in

0.15 s

0.3 s

0.05 s

0.1 s

The charging of inductance is given by
$I = I_{0} [1 - e^{- Rt / L}]$
$∴ \frac{I _{0}}{2} = I_{0} [1 - e^{- RT / L}]$
or $e^{- Rt / L} = \frac{1}{2}$ or $\frac{Rt}{L} =$ 1n 2
or $t = \frac{0.693 \times 300 \times 1 0 ^{- 3}}{2}$
= 0.1 s

Q. A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2 V. The current reaches half of its steady state value in