A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V. The total resistance bf.the circuit is 4Ω . What is the initial rate of growth of the current when the switch is closed ?

Question

A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V. The total resistance bf.the circuit is 4Ω . What is the initial rate of growth of the current when the switch is closed ? (A) 0.50 As-1 (B) 0.40 As-1 (C) 0.13 As-1 (D) 8.0 As-1

Tardigrade Admin · Accepted Answer

V = RI + L (dI/dt) , at t = 0 , I = 0, thus we have (dI/dt) = (V/L) = (1.6/0.2) = 8A/s

Q. A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V. The total resistance bf.the circuit is $4Ω$ . What is the initial rate of growth of the current when the switch is closed ?

$0.50 A s^{- 1}$

$0.40 A s^{- 1}$

$0.13 A s^{- 1}$

$8.0 A s^{- 1}$

$V = R I + L \frac{d I}{d t}, a t t = 0, I = 0,$ thus we have
$\frac{d I}{d t} = \frac{V}{L} = \frac{1.6}{0.2} = 8 A / s$

Q. A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V. The total resistance bf.the circuit is 4Ω . What is the initial rate of growth of the current when the switch is closed ?

0.50As−1

0.40As−1

0.13As−1

8.0As−1