A coil of 40 Ω resistance having 100 turns and radius 6 mm is connected to an ammeter of resistance of 160 ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, 32 μ C charge flows through it. The intensity of magnetic field will be

Question

A coil of 40 Ω resistance having 100 turns and radius 6 mm is connected to an ammeter of resistance of 160 ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, 32 μ C charge flows through it. The intensity of magnetic field will be (A) 6.55 T (B) 5.66 T (C) 0.655 T (D) 0.566 T

Tardigrade Admin · Accepted Answer

q=-(N/R)(B2-B1) A cos θ 32 × 10-4 =-(100/(160+40))(0-B) × π ×(6 × 10-3)2 × cos 0° ⇒ B =0.565 T

Q. A coil of $40 Ω$ resistance having $100$ turns and radius $6 mm$ is connected to an ammeter of resistance of $160$ ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, $32 μ C$ charge flows through it. The intensity of magnetic field will be

6.55 T

5.66 T

0.655 T

0.566 T

$q = - \frac{N}{R} (B_{2} - B_{1}) A cos θ$
$32 \times 1 0^{- 4}$
$= - \frac{100}{( 160 + 40 )} (0 - B) \times π \times (6 \times 1 0^{- 3})^{2} \times cos 0^{\circ}$
$\Rightarrow B = 0.565 T$

Q. A coil of 40Ω resistance having 100 turns and radius 6mm is connected to an ammeter of resistance of 160 ohms. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, 32μC charge flows through it. The intensity of magnetic field will be