A coil having n turns and resistance R Ω is connected with a galvanometer of resistance 4R Ω . This combination is moved in time t seconds from a magnetic flux φ1 Weber to φ2 Weber. The induced current in the circuit is

Question

A coil having n turns and resistance R Ω is connected with a galvanometer of resistance 4R Ω . This combination is moved in time t seconds from a magnetic flux φ1 Weber to φ2 Weber. The induced current in the circuit is (A) (φ2 - φ1/5Rnt)  (B)  - (n (φ2 - φ1)/5Rnt)  (C)  - ( (φ2 - φ1)/Rnt)  (D)  - ( n (φ2 - φ1)/Rt)

Tardigrade Admin · Accepted Answer

Given, Number of tums in coil =n We know that, Gument (i)=(e/R;)=(-Δ φ/R'Δ t) [∴ e=-Δ] R'=R+4 R i =-((φ2-φ1)/(R+4 R) Δ t) i =((φ2-φ1)/5 R(Δ t)) Here, coil have n number of turns. Hence, i=-(n(φ2-φ1)/5 R(Δ t)) Induced current, i=-(n(φ2-φ1)/5 R t)

Q. A coil having $n$ turns and resistance $R Ω$ is connected with a galvanometer of resistance $4 R Ω$ . This combination is moved in time $t$ seconds from a magnetic flux $ϕ_{1}$ Weber to $ϕ_{2}$ Weber. The induced current in the circuit is

$\frac{ϕ _{2} - ϕ _{1}}{5 R n t}$

$- \frac{n ( ϕ _{2} - ϕ _{1} )}{5 R n t}$

$- \frac{( ϕ _{2} - ϕ _{1} )}{R n t}$

$- \frac{n ( ϕ _{2} - ϕ _{1} )}{Rt}$

Q. A coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ . This combination is moved in time t seconds from a magnetic flux ϕ1​ Weber to ϕ2​ Weber. The induced current in the circuit is

5Rntϕ2​−ϕ1​​

−5Rntn(ϕ2​−ϕ1​)​

−Rnt(ϕ2​−ϕ1​)​

−Rtn(ϕ2​−ϕ1​)​

Given, Number of tums in coil =n We know that, Gument (i)=R;e​=R′Δt−Δϕ​ [∴e=−Δ] R′=R+4R i=−(R+4R)Δt(ϕ2​−ϕ1​)​ i=5R(Δt)(ϕ2​−ϕ1​)​ Here, coil have n number of turns. Hence, i=−5R(Δt)n(ϕ2​−ϕ1​)​ Induced current, i=−5Rtn(ϕ2​−ϕ1​)​

Q. A coil having $n$ turns and resistance $R Ω$ is connected with a galvanometer of resistance $4 R Ω$ . This combination is moved in time $t$ seconds from a magnetic flux $ϕ_{1}$ Weber to $ϕ_{2}$ Weber. The induced current in the circuit is

$\frac{ϕ _{2} - ϕ _{1}}{5 R n t}$

$- \frac{n ( ϕ _{2} - ϕ _{1} )}{5 R n t}$

$- \frac{( ϕ _{2} - ϕ _{1} )}{R n t}$

$- \frac{n ( ϕ _{2} - ϕ _{1} )}{Rt}$