A coil has a self inductance of 10 mH. What is the maximum magnitude of the induced emf in the inductor when a current I=0.1 sin 200 t A is sent through it?

Question

A coil has a self inductance of 10 mH. What is the maximum magnitude of the induced emf in the inductor when a current I=0.1 sin 200 t A is sent through it? (A) 0.3 V (B) 0.2 V (C) 0.1 V (D) 0.4 V

Tardigrade Admin · Accepted Answer

e = L ( dI / dt ) ( dI / dt )=( d / dt )(0.1 sin 200 t ) ( d I/ dt )=200 × 0.1 cos 200 t (( d I/ dt )) max =200 × 0.1 (for max = cos 200 t =1) e=L (d I/d t) ⇒ 10 × 10-3 × 200 × 0.1 e =0.2 V

Q. A coil has a self inductance of $10 m H$ . What is the maximum magnitude of the induced emf in the inductor when a current $I = 0.1 sin 200 t A$ is sent through it?

$0.3 V$

$0.2 V$

$0.1 V$

$0.4 V$

$e = L \frac{d I}{d t}$
$\frac{d I}{d t} = \frac{d}{d t} (0.1 sin 200 t)$
$\frac{d I}{d t} = 200 \times 0.1 cos 200 t$
$(\frac{d I}{d t})_{m a x} = 200 \times 0.1$ (for $max = cos 200 t = 1)$
$e = L \frac{d I}{d t}$
$\Rightarrow 10 \times 1 0^{- 3} \times 200 \times 0.1$
$e = 0.2 V$

Q. A coil has a self inductance of 10mH. What is the maximum magnitude of the induced emf in the inductor when a current I=0.1sin200tA is sent through it?

0.3V

0.2V

0.1V

0.4V