A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

Question

A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be (A) 2 (B) 10 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

From Dalton's law, final pressure of the mixture of nitrogen and oxygen is

P = P_{1} + P_{2}

= \frac{μ _{1} RT}{V} + \frac{μ _{2} RT}{V} = \frac{m _{1}}{M _{1}} \frac{RT}{V} + \frac{m _{2}}{M _{2}} \frac{RT}{V}

= \frac{8}{32} \frac{RT}{V} + \frac{7}{28} \frac{RT}{V} = \frac{RT}{2 V} \Rightarrow 10 = \frac{RT}{2 V}

.....(i)
When oxygen is absorbed then for nitrogen let pressure is

P = \frac{7}{28} \frac{RT}{4 V}

\Rightarrow P = \frac{RT}{4 T}

.....(ii)
From Eqs. (i) and (ii), we get pressure of the nitrogen

P = 5 a t m

Q. A closed vessel contains 8g of oxygen and 7g of nitrogen. The total pressure is 10atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

2

10

4

5

Q. A closed vessel contains $8 g$ of oxygen and $7 g$ of nitrogen. The total pressure is $10 a t m$ at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be