A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms -2 ) is of the order of :

Question

A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms -2 ) is of the order of : (A) 10-3 (B) 10-2 (C) 10-4 (D) 10-1

Tardigrade Admin · Accepted Answer

R=0.1 m ω=(2 π/ T )=(2 π/60)=0.105 rad / sec a=ω2 R =(0.105)2(0.1) =0.0011 =1.1 × 10-3 Average acceleration is of the order of 10-3

Q. A clock has a continuously moving second's hand of $0.1 m$ length. The average acceleration of the tip of the hand (in units of $m s^{- 2}$ ) is of the order of :

$1 0^{- 3}$

$1 0^{- 2}$

$1 0^{- 4}$

$1 0^{- 1}$

$R = 0.1 m$
$ω = \frac{2 π}{T} = \frac{2 π}{60} = 0.105 r a d / sec$
$a = ω^{2} R$
$= (0.105)^{2} (0.1)$
$= 0.0011$
$= 1.1 \times 1 0^{- 3}$
Average acceleration is of the order of $1 0^{- 3}$

Q. A clock has a continuously moving second's hand of 0.1m length. The average acceleration of the tip of the hand (in units of ms−2 ) is of the order of :

10−3

10−2

10−4

10−1