A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated besides each others ?

Question

A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated besides each others ? (A) 720 (B) 1440 (C) 3600 (D) 4320

Tardigrade Admin · Accepted Answer

Total no. of ways =(6-1) ! × 6p2 =5!× 30=120× 30 =3600

Q. A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated besides each others ?

$720$

$1440$

$3600$

$4320$

Total no. of ways $= (6 - 1)! \times^{6} p_{2}$
$= 5! \times 30 = 120 \times 30$
$= 3600$

Q. A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated besides each others ?

720

1440

3600

4320

Total no. of ways =(6−1)!×6p2​ =5!×30=120×30 =3600

$720$

$1440$

$3600$

$4320$

Total no. of ways $= (6 - 1)! \times^{6} p_{2}$
$= 5! \times 30 = 120 \times 30$
$= 3600$