A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. Find the angle in degrees which is subtended at the centre of hoop.

Question

A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. Find the angle in degrees which is subtended at the centre of hoop. (A) 21.5° (B) 23.5° (C) 22.5° (D) 24.5°

Tardigrade Admin · Accepted Answer

Length of wire = 2π × 3 = 6π cm and r = 48 cm is the radius of the hoop. Therefore the angle θ (in radian) subtended at the centre of the hoop is given by θ=( textArc / textRadius)=(6π/48) =(π/8)=22.5°

Q. A circular wire of radius $3 c m$ is cut and bent so as to lie along the circumference of a hoop whose radius is $48 c m$ . Find the angle in degrees which is subtended at the centre of hoop.

$21. 5^{\circ}$

$23. 5^{\circ}$

$22. 5^{\circ}$

$24. 5^{\circ}$

Length of wire $= 2 π \times 3 = 6 π c m$ and $r = 48 c m$ is the radius of the hoop. Therefore the angle $θ$ (in radian) subtended at the centre of the hoop is given by
$θ = \frac{Arc}{Radius} = \frac{6 π}{48}$
$= \frac{π}{8} = 22. 5^{\circ}$

Q. A circular wire of radius 3cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48cm. Find the angle in degrees which is subtended at the centre of hoop.

21.5∘

23.5∘

22.5∘

24.5∘