A circular plane sheet of radius 10 cm is placed in a uniform electric field of 5 × 105 N C-1, making an angle of 60° with the field. The electric flux through the sheet is

Question

A circular plane sheet of radius 10 cm is placed in a uniform electric field of 5 × 105 N C-1, making an angle of 60° with the field. The electric flux through the sheet is (A) 1.36 × 102 N m2 C-1 (B) 1.36 × 104 N m2 C-1 (C) 0.515 × 102 N m2 C-1 (D) 0.515 × 104 N m2 C-1

Tardigrade Admin · Accepted Answer

Here, r = 10 cm = 0.1 m, E = 5 × 105 N C-1 As the angle between the plane sheet and the electric field is 60°, angle made by the normal to the plane sheet and the electric field is θ = 90° - 60° = 30° φE=ES cosθ=E×π r2 cosθ =5×105×3.14×(0.1)2cos30°=1.36×104 N m2 C-1

Q. A circular plane sheet of radius $10 c m$ is placed in a uniform electric field of $5 \times 1 0^{5} N C^{- 1}$ , making an angle of $6 0^{°}$ with the field. The electric flux through the sheet is

$1.36 \times 1 0^{2} N m^{2} C^{- 1}$

$1.36 \times 1 0^{4} N m^{2} C^{- 1}$

$0.515 \times 1 0^{2} N m^{2} C^{- 1}$

$0.515 \times 1 0^{4} N m^{2} C^{- 1}$

Q. A circular plane sheet of radius 10cm is placed in a uniform electric field of 5×105NC−1, making an angle of 60° with the field. The electric flux through the sheet is

1.36×102Nm2C−1

1.36×104Nm2C−1

0.515×102Nm2C−1

0.515×104Nm2C−1

Here, r=10cm=0.1m, E=5×105NC−1 As the angle between the plane sheet and the electric field is 60°, angle made by the normal to the plane sheet and the electric field is θ=90°−60°=30° ϕE​=EScosθ=E×πr2cosθ =5×105×3.14×(0.1)2cos30°=1.36×104Nm2C−1

Q. A circular plane sheet of radius $10 c m$ is placed in a uniform electric field of $5 \times 1 0^{5} N C^{- 1}$ , making an angle of $6 0^{°}$ with the field. The electric flux through the sheet is

$1.36 \times 1 0^{2} N m^{2} C^{- 1}$

$1.36 \times 1 0^{4} N m^{2} C^{- 1}$

$0.515 \times 1 0^{2} N m^{2} C^{- 1}$

$0.515 \times 1 0^{4} N m^{2} C^{- 1}$