A circular loop of area 0.01 m 2 carrying a current of 10 A, is held perpendicular to a magnetic field of intensity 0.1 T. The torque acting on the loop is

Question

A circular loop of area 0.01 m 2 carrying a current of 10 A, is held perpendicular to a magnetic field of intensity 0.1 T. The torque acting on the loop is (A) 0.001 N m (B) 0.8 N m (C) zero (D) 0.01 N m

Tardigrade Admin · Accepted Answer

Area ( A )=0.01 m 2; Current ( I )=10 A; Angle (φ)=90° and magnetic field (B)=0.1 T. Therefore acutal angle θ=(90°-φ)=(90°-90°)=0°. And torque acting on the loop (τ)=I A B sin θ =10 × 0.01 × 0.1 × sin 0°=0.

Q. A circular loop of area 0.01m2 carrying a current of 10A, is held perpendicular to a magnetic field of intensity 0.1T. The torque acting on the loop is

0.001 N m

0.8 N m

zero

0.01 N m

Area (A)=0.01m2​; Current (I)=10A; Angle (ϕ)=90∘ and magnetic field (B)=0.1T. Therefore acutal angle θ=(90∘−ϕ)=(90∘−90∘)=0∘. And torque acting on the loop (τ)=IABsinθ =10×0.01×0.1×sin0∘=0.

Q. A circular loop of area $0.01 m^{2}$ carrying a current of $10 A$ , is held perpendicular to a magnetic field of intensity $0.1 T$ . The torque acting on the loop is