Question

A circular disc with a groove along its diameter is placed horizontally. A block of mass $1kg$ is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is $\mu =2/5$. The disc has an acceleration of $25m/s^2$ Find the acceleration of the block with respect to disc. _____ $m/s^2$

Answer 1

Normal reaction in vertical direction $N_1=mg$
Normal reaction from side to the groove $N_2=ma\sin 37^{\circ }$
Therefore, acceleration of block with respect to disc
$a_r=\frac{ma\cos 37^{\circ }=\mu N_1-\mu N_2}{m}$
Substituting the values we get, $a^r=10m/s^2$