A circular disc of radius 0.2 m is placed in a uniform magnetic field of induction (1/π)(( Wb / m 2)) in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is:

Question

A circular disc of radius 0.2 m is placed in a uniform magnetic field of induction (1/π)(( Wb / m 2)) in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is: (A) 0.02 Wb (B) 0.06 Wb (C) 0.04 Wb (D) 0.01 Wb

Tardigrade Admin · Accepted Answer

φ=B A cos θ <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/82c881724d472137fa215bc7360fe59b-.png" /> ∴ φ =(1/π) × π(0.2)2 × cos 60° =(0.2)2 × (1/2)=0.02 Wb

Q. A circular disc of radius $0.2 m$ is placed in a uniform magnetic field of induction $\frac{1}{π} (\frac{Wb}{m ^{2}})$ in such a way that its axis makes an angle of $6 0^{\circ}$ with B. The magnetic flux linked with the disc is:

$0.02 Wb$

$0.06 Wb$

$0.04 Wb$

$0.01 Wb$

$ϕ = B A cos θ$

$∴ ϕ = \frac{1}{π} \times π (0.2)^{2} \times cos 6 0^{\circ}$
$= (0.2)^{2} \times \frac{1}{2} = 0.02 Wb$

Q. A circular disc of radius 0.2m is placed in a uniform magnetic field of induction π1​(m2Wb​) in such a way that its axis makes an angle of 60∘ with B. The magnetic flux linked with the disc is:

0.02Wb

0.06Wb

0.04Wb

0.01Wb