A circular coil of wire consisting of 100 turns each of radius 9 cm carries a current of 0.4 A. The magnitude of the magnetic field at the centre of coil is [μ0 =12.56 × 1-7 SI Unit]

Question

A circular coil of wire consisting of 100 turns each of radius 9 cm carries a current of 0.4 A. The magnitude of the magnetic field at the centre of coil is [μ0 =12.56 × 1-7 SI Unit] (A) 2.4 × 10-11 T (B) 2.79× 10-5 T (C) 2.79 × 10-4 T (D) 2.79 × 10-3 T

Tardigrade Admin · Accepted Answer

Given, number of turns, n=100, radius of coil, r=9 cm =9 × 10-2 m and current flow in the coil, I=0.4 A The magnitude of the magnetic field at the centre of a coil of n turns is given by B=(μ0 n I/2 r) ...(i) Substituting given values in Eq. (i), we get ⇒ B =(1256 × 10-7 × 100 × 0.4/2 × 10-1 × 9 × 10-2) =2.79 × 10-4 T

Q. A circular coil of wire consisting of $100$ turns each of radius $9 c m$ carries a current of $0.4 A$ . The magnitude of the magnetic field at the centre of coil is [ $μ_{0} = 12.56 \times 1^{- 7}$ SI Unit]

$2.4 \times 1 0^{- 11} T$

$2.79 \times 1 0^{- 5} T$

$2.79 \times 1 0^{- 4} T$

$2.79 \times 1 0^{- 3} T$

Q. A circular coil of wire consisting of 100 turns each of radius 9cm carries a current of 0.4A. The magnitude of the magnetic field at the centre of coil is [μ0​=12.56×1−7 SI Unit]

2.4×10−11T

2.79×10−5T

2.79×10−4T

2.79×10−3T

Q. A circular coil of wire consisting of $100$ turns each of radius $9 c m$ carries a current of $0.4 A$ . The magnitude of the magnetic field at the centre of coil is [ $μ_{0} = 12.56 \times 1^{- 7}$ SI Unit]

$2.4 \times 1 0^{- 11} T$

$2.79 \times 1 0^{- 5} T$

$2.79 \times 1 0^{- 4} T$

$2.79 \times 1 0^{- 3} T$