A circular coil of one turn in formed by a 6.28 m length wire, which carries a current of 3.14 A. The magnetic field at the centre of coil is:

Question

A circular coil of one turn in formed by a 6.28 m length wire, which carries a current of 3.14 A. The magnetic field at the centre of coil is: (A) 1 × 10-6 T (B) 4 × 10-6 T (C) 0.5 × 10-6 T (D) 2 × 10-6 T

Tardigrade Admin · Accepted Answer

Magnetic field due to circular Loop at center =(μ0 I /2 R ) l=2 π R =6.28 ⇒ R =1 B =(μ0 I /2 × 1)=(4 × π × 10-7 × 3.14/2) π2=10 ⇒ B=2 × 10-7 × π2=10 ⇒ B =2 × 10-7 × 10 =2 × 10-6 T

Q. A circular coil of one turn in formed by a $6.28 m$ length wire, which carries a current of $3.14 A$ . The magnetic field at the centre of coil is:

$1 \times 1 0^{- 6} T$

$4 \times 1 0^{- 6} T$

$0.5 \times 1 0^{- 6} T$

$2 \times 1 0^{- 6} T$

Q. A circular coil of one turn in formed by a 6.28m length wire, which carries a current of 3.14A. The magnetic field at the centre of coil is:

1×10−6T

4×10−6T

0.5×10−6T

2×10−6T

Magnetic field due to circular Loop at center =2Rμ0​I​ l=2πR=6.28⇒R=1 B=2×1μ0​I​=24×π×10−7×3.14​ π2=10⇒B=2×10−7× π2=10⇒B=2×10−7×10 =2×10−6T

Q. A circular coil of one turn in formed by a $6.28 m$ length wire, which carries a current of $3.14 A$ . The magnetic field at the centre of coil is:

$1 \times 1 0^{- 6} T$

$4 \times 1 0^{- 6} T$

$0.5 \times 1 0^{- 6} T$

$2 \times 1 0^{- 6} T$