A circuit contain two resistors R1 and R2 in series. Find the ratio of input voltage to voltage to R2

Question

A circuit contain two resistors R1 and R2 in series. Find the ratio of input voltage to voltage to R2 (A) (R2/R1+R2) (B) (R1+R2/R2) (C) (R1+R2/R1) (D) (R1/R1+R2)

Tardigrade Admin · Accepted Answer

Input voltage, is voltage across (R1+R2), is given by, V=i(R1+R2) V text Oltage across R2=i . R2 So ⇒ (Vi text input /VR2)=((R1+R2)/-(R2) ⋅s)

Q. A circuit contain two resistors $R_{1}$ and $R_{2}$ in series. Find the ratio of input voltage to voltage to $R_{2}$

$\frac{R _{2}}{R _{1} + R _{2}}$

$\frac{R _{1} + R _{2}}{R _{2}}$

$\frac{R _{1} + R _{2}}{R _{1}}$

$\frac{R _{1}}{R _{1} + R _{2}}$

Input voltage, is voltage across $(R_{1} + R_{2})$ , is given by,
$V = i (R_{1} + R_{2})$
$V_{Oltage across} R_{2} = i . R_{2}$
So $\Rightarrow \frac{V _{i input}}{V _{R_{2}}} = \frac{( R _{1} + R _{2} )}{- ( R _{2} ) \dots}$

Q. A circuit contain two resistors R1​ and R2​ in series. Find the ratio of input voltage to voltage to R2​

R1​+R2​R2​​

R2​R1​+R2​​

R1​R1​+R2​​

R1​+R2​R1​​