A circle passes through (-2, 4) and touches the y-axis at (0, 2). Which one of the following equations can represent a diameter of this circle ?

Question

A circle passes through (-2, 4) and touches the y-axis at (0, 2). Which one of the following equations can represent a diameter of this circle ? (A) 4x + 5y - 6 = 0 (B) 2x - 3y + 10 = 0 (C) 3x+ 4y - 3 = 0 (D) 5x + 2y + 4 = 0

Tardigrade Admin · Accepted Answer

(r-2)2+22+r2 ⇒ r=2 ⇒ centre is ⇒ diameter can be (-2,2) 2x-3y+10=0

Q. A circle passes through (-2, 4) and touches the y-axis at (0, 2). Which one of the following equations can represent a diameter of this circle ?

$4 x + 5 y - 6 = 0$

$2 x - 3 y + 10 = 0$

$3 x + 4 y - 3 = 0$

$5 x + 2 y + 4 = 0$

$(r - 2)^{2} + 2^{2} + r^{2} \Rightarrow r = 2$
$\Rightarrow$ centre is $\Rightarrow$ diameter can be
$(- 2, 2) 2 x - 3 y + 10 = 0$

Q. A circle passes through (-2, 4) and touches the y-axis at (0, 2). Which one of the following equations can represent a diameter of this circle ?

4x+5y−6=0

2x−3y+10=0

3x+4y−3=0

5x+2y+4=0

(r−2)2+22+r2⇒r=2 ⇒ centre is ⇒ diameter can be (−2,2)2x−3y+10=0

$4 x + 5 y - 6 = 0$

$2 x - 3 y + 10 = 0$

$3 x + 4 y - 3 = 0$

$5 x + 2 y + 4 = 0$

$(r - 2)^{2} + 2^{2} + r^{2} \Rightarrow r = 2$
$\Rightarrow$ centre is $\Rightarrow$ diameter can be
$(- 2, 2) 2 x - 3 y + 10 = 0$