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Tardigrade
Question
Physics
A child is swinging a swing. Minimum and maximum heights of swing from earths surface are 0.75 m and 2 m respectively. The maximum velocity of this swing is
Q. A child is swinging a swing. Minimum and maximum heights of swing from earths surface are
0.75
m
and
2
m
respectively. The maximum velocity of this swing is
1519
117
Punjab PMET
Punjab PMET 2009
Oscillations
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A
5
m
s
−
1
15%
B
10
m
s
−
1
19%
C
15
m
s
−
1
60%
D
17
m
s
−
1
6%
Solution:
According to law of conservation of energy
2
1
m
v
m
a
x
2
=
m
g
(
h
2
−
h
1
)
⇒
v
m
a
x
=
2
g
(
h
2
−
h
1
)
=
2
×
10
×
(
2
−
0.75
)
=
2
×
10
×
1.25
=
25
=
5
m
s
−
1