A charged spherical conductor of radius a and charge q, is surrounded by another charged concentric sphere of radius b(ba). The potential difference between conductors is V. When, the spherical conductor of radius b is discharged completely, then the potential difference between conductor will be

Question

A charged spherical conductor of radius a and charge q, is surrounded by another charged concentric sphere of radius b(b>a). The potential difference between conductors is V. When, the spherical conductor of radius b is discharged completely, then the potential difference between conductor will be (A) V (B)  (Va/b)  (C) (q1/4 π ε0 a)-(q2/4 π ε0 b) (D) None of the above

Tardigrade Admin · Accepted Answer

Since, potential difference between spheres depends upon electric field present in the space between spheres, the electric field in the space between spheres due to outer. sphere is zero. So, potential difference between spheres does not depend upon the charge on outer sphere.

$V$

$\frac{V _{a}}{b}$

$\frac{q _{1}}{4 π ε _{0} a} - \frac{q _{2}}{4 π ε _{0} b}$

None of the above

Since, potential difference between spheres depends upon electric field present in the space between spheres, the electric field in the space between spheres due to outer. sphere is zero. So, potential difference between spheres does not depend upon the charge on outer sphere.

V

bVa​​

4πε0​aq1​​−4πε0​bq2​​

None of the above

Since, potential difference between spheres depends upon electric field present in the space between spheres, the electric field in the space between spheres due to outer. sphere is zero. So, potential difference between spheres does not depend upon the charge on outer sphere.

$V$

$\frac{V _{a}}{b}$

$\frac{q _{1}}{4 π ε _{0} a} - \frac{q _{2}}{4 π ε _{0} b}$