Question

A charged particle oscillates about its mean equilibrium position with a frequency of $10^{9}Hz$. The wavelength (in $m$ ) of electromagnetic waves produced will be

Answer 1

Answer: 0.30

As given that, the frequency of the charged particles oscillating about its mean equilibrium position is $109Hz$.
Vibrating particle produces electric and magnetic field.
So, frequency of electromagnetic waves produced by the charged particle is $v=10^{9}Hz$.
$\therefore$ Wavelength, $\lambda =\frac{c}{v}$
$=\frac{3\times 10^8}{10^9}=0.3m$