Question

A charged particle oscillates about its mean equilibrium position with a frequency of $10^{9} Hz$. The wavelength (in $m$ ) of electromagnetic waves produced will be

Answer 1

As given that, the frequency of the charged particles oscillating about its mean equilibrium position is $109 \,Hz$.
Vibrating particle produces electric and magnetic field.
So, frequency of electromagnetic waves produced by the charged particle is $v=10^{9} Hz$.
$\therefore $ Wavelength, $\lambda=\frac{c}{v}$
$=\frac{3 \times 10^{8}}{10^{9}}=0.3 \,m$