A charged particle of mass ' m ' and charge ' q ' is released from rest in an uniform electric field vec E . Neglecting the effect of gravity, the kinetic energy of the charged particle after ' t ' seconds is

Question

A charged particle of mass ' m ' and charge ' q ' is released from rest in an uniform electric field vec E . Neglecting the effect of gravity, the kinetic energy of the charged particle after ' t ' seconds is (A) ( text Eqm /t) (B) ( E 2 q 2 t 2/2 m ) (C) (2 E 2 t 2/ mq ) (D) ( E 2 q 2 m /2 t 2)

Tardigrade Admin · Accepted Answer

K . E =(1/2) mv 2 =(1/2) m (0+( Eq / m ) t )2

Q. A charged particle of mass ' $m$ ' and charge ' $q$ ' is released from rest in an uniform electric field $E$ . Neglecting the effect of gravity, the kinetic energy of the charged particle after ' $t$ ' seconds is

$\frac{Eqm}{t}$

$\frac{E ^{2} q ^{2} t ^{2}}{2 m}$

$\frac{2 E ^{2} t ^{2}}{m q}$

$\frac{E ^{2} q ^{2} m}{2 t ^{2}}$

$K . E = \frac{1}{2} m v^{2}$
$= \frac{1}{2} m (0 + \frac{Eq}{m} t)^{2}$

Q. A charged particle of mass ' m ' and charge ' q ' is released from rest in an uniform electric field E. Neglecting the effect of gravity, the kinetic energy of the charged particle after ' t ' seconds is

t Eqm ​

2mE2q2t2​

mq2E2t2​

2t2E2q2m​