A charged particle moving in a magnetic field experiences a resultant force

Question

A charged particle moving in a magnetic field experiences a resultant force (A) In the direction opposite to the field (B) In the direction of field (C) In the direction perpendicular to both the field and its velocity (D) None of the above

Tardigrade Admin · Accepted Answer

As overset arrow F = q (. overset arrow v × overset arrow B .) Thus, force perpendicular to both the vectors velocity and magnetic field.

Q. A charged particle moving in a magnetic field experiences a resultant force

In the direction opposite to the field

In the direction of field

In the direction perpendicular to both the field and its velocity

None of the above

As $F \to = q (v \to \times B \to)$
Thus, force perpendicular to both the vectors velocity and magnetic field.

Q. A charged particle moving in a magnetic field experiences a resultant force

In the direction opposite to the field

In the direction of field

In the direction perpendicular to both the field and its velocity

None of the above

As F→=q(v→×B→) Thus, force perpendicular to both the vectors velocity and magnetic field.

As $F \to = q (v \to \times B \to)$
Thus, force perpendicular to both the vectors velocity and magnetic field.