A charged particle moves through a magnetic field in a direction perpendicular to it. Then the

Question

A charged particle moves through a magnetic field in a direction perpendicular to it. Then the (A) acceleration remains unchanged (B) velocity remains unchanged (C) speed of the particle remains unchanged (D) direction of the particle remains unchanged

Tardigrade Admin · Accepted Answer

If a moving charged particle is subjected to a perpendicular uniform magnetic field, then according to F=q v B sin θ, it will experience a maximum force which will provide the centripetal force to particle and it will describe a circular path with uniform speed.

Q. A charged particle moves through a magnetic field in a direction perpendicular to it. Then the

acceleration remains unchanged

velocity remains unchanged

speed of the particle remains unchanged

direction of the particle remains unchanged

If a moving charged particle is subjected to a perpendicular uniform magnetic field, then according to $F = q v B sin θ$ , it will experience a maximum force which will provide the centripetal force to particle and it will describe a circular path with uniform speed.

Q. A charged particle moves through a magnetic field in a direction perpendicular to it. Then the

acceleration remains unchanged

velocity remains unchanged

speed of the particle remains unchanged

direction of the particle remains unchanged

If a moving charged particle is subjected to a perpendicular uniform magnetic field, then according to F=qvBsinθ, it will experience a maximum force which will provide the centripetal force to particle and it will describe a circular path with uniform speed.

If a moving charged particle is subjected to a perpendicular uniform magnetic field, then according to $F = q v B sin θ$ , it will experience a maximum force which will provide the centripetal force to particle and it will describe a circular path with uniform speed.