A charge +q is placed at origin. There are two concentric spherical surfaces; S1 of radius R and S2 of radius 2R. Both the surfaces have their centres at the origin. Let φ1 denote the flux through S1 and φ2 the flux through S2. The relation between φ1 and φ2 is

Question

A charge +q is placed at origin. There are two concentric spherical surfaces; S1 of radius R and S2 of radius 2R. Both the surfaces have their centres at the origin. Let φ1 denote the flux through S1 and φ2 the flux through S2. The relation between φ1 and φ2 is (A) φ1 = 2 φ2 (B) φ1 = φ2 /2 (C) φ1 = 4φ2 (D) φ1 = φ2

Tardigrade Admin · Accepted Answer

According to gauss law, φ = (q/ε0) ∴ : :: φ1 = φ2 = (q/ε0)

$ϕ_{1} = 2 ϕ_{2}$

$ϕ_{1} = ϕ_{2} /2$

$ϕ_{1} = 4 ϕ_{2}$

$ϕ_{1} = ϕ_{2}$

According to gauss law,
$ϕ = \frac{q}{ε _{0}}$
$∴ ϕ_{1} = ϕ_{2} = \frac{q}{ε _{0}}$

Q. A charge +q is placed at origin. There are two concentric spherical surfaces; S1​ of radius R and S2​ of radius 2R. Both the surfaces have their centres at the origin. Let ϕ1​ denote the flux through S1​ and ϕ2​ the flux through S2​. The relation between ϕ1​ and ϕ2​ is

ϕ1​=2ϕ2​

ϕ1​=ϕ2​/2

ϕ1​=4ϕ2​

ϕ1​=ϕ2​

According to gauss law, ϕ=ε0​q​ ∴ϕ1​=ϕ2​=ε0​q​

$ϕ_{1} = 2 ϕ_{2}$

$ϕ_{1} = ϕ_{2} /2$

$ϕ_{1} = 4 ϕ_{2}$

$ϕ_{1} = ϕ_{2}$

According to gauss law,
$ϕ = \frac{q}{ε _{0}}$
$∴ ϕ_{1} = ϕ_{2} = \frac{q}{ε _{0}}$