A charge +Q at A (see figure) produces electric field E and electric potential V at D. If we now put charges -2 Q and + Q at B and C respectively, then the electric field and potential at D will be

Question

A charge +Q at A (see figure) produces electric field E and electric potential V at D. If we now put charges -2 Q and + Q at B and C respectively, then the electric field and potential at D will be (A) E and 0 (B) 0 and V (C) √2 E and ( V /√2) (D) ( E /√2) and ( V /√2)

Tardigrade Admin · Accepted Answer

When charges -2 Q and +Q are placed at B and C respectively, V'=(1/4 π ε0)[(Q/a)-(2 Q/a)+(Q/a)]= text zero This settles in favour of (a).

Q. A charge $+ Q$ at $A$ (see figure) produces electric field E and electric potential $V$ at D. If we now put charges $- 2 Q$ and $+ Q$ at $B$ and $C$ respectively, then the electric field and potential at D will be

$E$ and 0

0 and $V$

$2 E$ and $\frac{V}{2}$

$\frac{E}{2}$ and $\frac{V}{2}$

When charges $- 2 Q$ and $+ Q$ are placed at $B$ and $C$ respectively,
$V^{'} = \frac{1}{4 π ε _{0}} [\frac{Q}{a} - \frac{2 Q}{a} + \frac{Q}{a}] = zero$
This settles in favour of (a).

Q. A charge +Q at A (see figure) produces electric field E and electric potential V at D. If we now put charges −2Q and +Q at B and C respectively, then the electric field and potential at D will be

E and 0

0 and V

2​E and 2​V​

2​E​ and 2​V​