A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given: 1 a.m.u = 931 MeV )

Question

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given: 1 a.m.u = 931 MeV ) (A) 26.7 MeV (B) 6.675 MeV (C) 13.35 MeV (D) 2.67 MeV

Tardigrade Admin · Accepted Answer

Mass defect Δ m =0.02866 a.m.u. Energy =0.02866 × 931=26.7 MeV As 1 H 2+ 1 H 2 longrightarrow 2 He 4 Energy liberated per a.m.u=13.35/2 MeV =6.675 MeV

Q. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is $0.02866$ a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u = $931 M e V$ )

$26.7 M e V$

$6.675 M e V$

$13.35 M e V$

$2.67 M e V$

Mass defect $Δ m = 0.02866$ a.m.u.
Energy $= 0.02866 \times 931 = 26.7 M e V$
As $_{1} H^{2} +_{1} H^{2} ⟶_{2} H e^{4}$
Energy liberated per a.m.u=13.35/2{\,} MeV $= 6.675 M e V$

Q. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u = 931MeV )

26.7MeV

6.675MeV

13.35MeV

2.67MeV