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  4. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given: 1 a.m.u = 931 MeV )

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Q. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is $0.02866$ a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u = $931\, MeV$ )

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Solution:

Mass defect $\Delta m =0.02866$ a.m.u.
Energy $=0.02866 \times 931=26.7 \,MeV$
As ${ }_1 H ^2+{ }_1 H ^2 \longrightarrow{ }_2 He ^4$
Energy liberated per a.m.u=13.35/2\, MeV $=6.675 \,MeV$