A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in copper sulphate solution?

Question

A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in copper sulphate solution? (A) 31.8 g (B) 16.0 g (C) 12.7 g (D) 63.5 g

Tardigrade Admin · Accepted Answer

( text MassofHydrogen / text Massofcopper ) =( text EquivalentmassofHydrogen / text Equivalentmassofcopper ) ⇒ (0.504/ text Massofcopper )=(1/63.5 / 2) ⇒ Mass of copper deposited =16.0 g

Q. A certain current liberated $0.504 g$ of hydrogen in $2$ hours. How many grams of copper can be liberated by the same current flowing for the same time in copper sulphate solution?

31.8 g

16.0 g

12.7 g

63.5 g

$\frac{MassofHydrogen}{Massofcopper}$

$= \frac{EquivalentmassofHydrogen}{Equivalentmassofcopper}$

$\Rightarrow \frac{0.504}{Massofcopper} = \frac{1}{63.5/2}$

$\Rightarrow$ Mass of copper deposited $= 16.0 g$

Q. A certain current liberated 0.504g of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in copper sulphate solution?