A certain charge 2Q is divided at first into two parts q1 and q2. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then (Q/q1) =

Question

A certain charge 2Q is divided at first into two parts q1 and q2. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then (Q/q1) = (A) 1 (B) 4 (C) 0.5 (D) 2

Tardigrade Admin · Accepted Answer

For force F to be maximum between charges q1 and q2, q1=q2=(2 Q/2)=Q Now (Q/q1)=(Q/Q)=1

Q. A certain charge 2Q is divided at first into two parts q₁ and q₂. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then $\frac{Q}{q _{1}}$ =

1

4

0.5

2

For force F to be maximum between charges $q_{1} an d q_{2}, q_{1} = q_{2} = \frac{2 Q}{2} = Q$
$N o w \frac{Q}{q _{1}} = \frac{Q}{Q} = 1$

Q. A certain charge 2Q is divided at first into two parts q1 and q2. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then q1​Q​ =

1

4

0.5

2

For force F to be maximum between charges q1​andq2​,q1​=q2​=22Q​=Q Nowq1​Q​=QQ​=1

Q. A certain charge 2Q is divided at first into two parts q₁ and q₂. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then $\frac{Q}{q _{1}}$ =

For force F to be maximum between charges $q_{1} an d q_{2}, q_{1} = q_{2} = \frac{2 Q}{2} = Q$
$N o w \frac{Q}{q _{1}} = \frac{Q}{Q} = 1$