A cell of emf E is connected with an external resistance R, then potential difference across cell is V. The internal resistance of a cell will be

Question

A cell of emf E is connected with an external resistance R, then potential difference across cell is V. The internal resistance of a cell will be (A) ((E-V) R/E) (B) ((E-V) R/V) (C) (( V - E ) R / V ) (D) (( V - E ) R / E )

Tardigrade Admin · Accepted Answer

Let the current in the circuit be I = (V/R) Across the cell, V=E- Ir r=(E-V/I) ⇒ (E-V/V / R) r=((E-V/V)) R

Q. A cell of emf $E$ is connected with an external resistance $R$ , then potential difference across cell is $V$ . The internal resistance of a cell will be

$\frac{( E - V ) R}{E}$

$\frac{( E - V ) R}{V}$

$\frac{( V - E ) R}{V}$

$\frac{( V - E ) R}{E}$

Let the current in the circuit be $I = \frac{V}{R}$
Across the cell, $V = E -$ Ir
$r = \frac{E - V}{I} \Rightarrow \frac{E - V}{V / R}$
$r = (\frac{E - V}{V}) R$

Q. A cell of emf E is connected with an external resistance R, then potential difference across cell is V. The internal resistance of a cell will be

E(E−V)R​

V(E−V)R​

V(V−E)R​

E(V−E)R​