A carrier wave of peak voltage 12 V is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of 75 % 3 N volt then N is?

Question

A carrier wave of peak voltage 12 V is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of 75 % 3 N volt then N is? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Modulation index =(75/100)=(Am/Ac) ⇒ Am=(75/100)× Ac=(75/100)× 12=9 volt

Q. A carrier wave of peak voltage $12 V$ is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of $75%$ $3 N$ volt then $N$ is?

Modulation index $= \frac{75}{100} = \frac{A _{m}}{A _{c}}$
$\Rightarrow A_{m} = \frac{75}{100} \times A_{c} = \frac{75}{100} \times 12 = 9$ volt

Q. A carrier wave of peak voltage 12V is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of 75% 3N volt then N is?

Modulation index =10075​=Ac​Am​​ ⇒Am​=10075​×Ac​=10075​×12=9 volt

Q. A carrier wave of peak voltage $12 V$ is used to transmit a message signal. The peak voltage of the modulating signal in order to have a modulation index of $75%$ $3 N$ volt then $N$ is?

Modulation index $= \frac{75}{100} = \frac{A _{m}}{A _{c}}$
$\Rightarrow A_{m} = \frac{75}{100} \times A_{c} = \frac{75}{100} \times 12 = 9$ volt